How to check for number of linked issues using expressions

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1

I’m using ScriptRunner to add a scripted validator to a workflow transition. I’m having some issues getting the expression I need correct and hoping someone can help.

What I’m trying to do:

  1. Check current issue type; should be Bug or Story
  2. Check the linked issues to see if at least one is either a Test or a Test Set
  3. If both return true, allow the transition

The following expression code runs perfectly until I try running it against a Bug or Story that doesn’t have any linked issues. It then returns true, even though it should be false. What do I need to add/change to make this return false if there are no linked issues?

issue.issueType.name.match('^(Bug|Story)$') != null
&& 
issue.links.map(l => l.linkedIssue)
	.filter(s => s.issueType.name.match('^(Test|Test Set)$'))
	.length == issue.links.map(l => l.linkedIssue).length
2

The second part of your condition:

issue.links.map(l => l.linkedIssue)
	.filter(s => s.issueType.name.match('^(Test|Test Set)$'))
	.length == issue.links.map(l => l.linkedIssue).length

Counts the number of linked issues of type (Test|Test Set) and compares this number with number of all links. If there are no links the number will be 0 in both cases and 0 == 0 is true so your condition returns true if there are no links.

So I suggest adding issue.links.length > 0.

Your 2nd condition will return false if there are any additonal issue links that do not point to Test | Test Sets. E.g. if there is a “duplicates” link to another bug, the condtion will return false. If that’s what you intend, the expression would be:

issue.issueType.name.match('^(Bug|Story)$') != null
&& 
issue.links.length > 0
&&
issue.links.map(l => l.linkedIssue)
	.filter(s => s.issueType.name.match('^(Test|Test Set)$'))
	.length == issue.links.map(l => l.linkedIssue).length

If you only want to check if at least one link to a Test | Test Set exists, it could be written as:

issue.issueType.name.match('^(Bug|Story)$') != null
&&
issue.links.length > 0
&&
issue.links.map(l => l.linkedIssue)
	.filter(s => s.issueType.name.match('^(Test|Test Set)$'))
	.length > 0
1 Like
3

Thank you! I was a PHP and python dev for 20 years, but the functional programming stuff is completely new to me and I’m stumbling my way through.